A.x3=x1+x2B.x1x2=x1x3+x2x3C.x3+x1+x2=0D.x1x2+x1x3+x2x3=0在线课程B
分析:由题意知
,整理得ax2-kx-b=0,由题设条件知
,
,
.由此可知x1x3+x2x3=(x1+x2)x3=
=-
=x1x2.解答:
,∴ax2=kx+b,整理得ax2-kx-b=0,
由题设条件知
,
,
.∴x1x3+x2x3=(x1+x2)x3=
=-
=x1x2.故选B.
点评:本题考查直线和抛物线的位置关系,解题时要认真审题,仔细解答.
编辑:chaxungu时间:2026-04-27 14:32:14分类:高中数学题库
,整理得ax2-kx-b=0,由题设条件知
,
,
.由此可知x1x3+x2x3=(x1+x2)x3=
=-
=x1x2.
,
,
,
.
=-
=x1x2.