(2)
=________.(3)
=________.(4)125+
=________.(5)
=________.在线课程解::(1)(lg2)2+lg2•lg50+lg25=(lg2)2+lg2•(2-lg2)+2lg5
=2(lg2+lg5)=2.
(2)

=2+
-
=3.(3)

=

=5.
(4)125+

=125+4+7-3
=133.
(5)

=2×

=2
.分析:(1)由lg50=2-lg2,原式可转化为2(lg2+lg5),由此能求出其结果.
(2)
,
,
,由此能导出原式的值.(3)
,
,由此能求出原式的值.(4)
,由此能求出原式的值.(5)
=2×
,由此能求出原式的值.点评:本题考查对数的性质和运算法则,解题时要注意公式的合理运用.